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SOLUTIONS
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TOPIC: SOLUTIONS
#471
Re:SOLUTIONS 2 Years, 5 Months ago Karma: 0

1)An elecrolyte A gives 3ions and B is a non electrolyte.if 0.1M solution of B produces an osmotic pressure P,then 0.05M solution of A will produce an osmotic pressure,assuming that the electrolyte is completely ionised...............


a)1.5P   b)P   c).5P   d).75P


2)The relationship between the values of osmotic pressure of .1M solutions of KNO3(P1) and CH3COOH(P2) is........


a)P1=P2  b)P2>P1  c)P1/P1+P2=P2/P1+P2  d)P1>P2...Explain with reasons


 







Nandita
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#472
Re:SOLUTIONS 2 Years, 5 Months ago Karma: 0
Q1 : - P = i CRT

P = osmotic pressure
i = Von't Hoff factor = 1+(n-1)a

where ,
a=degree of dissociation of an electrolyte and
n = not of species into which it dissociates

C = conc. of solution
R = gas constant , T = temperature

Now for non electrolyte i=1
So for B i=1 => P=CRT = 0.1 RT

=> RT =10P

For A
i = 1+(3-1)a ( a = 1 since it completely dissociates/ ionizes )
=> i = 1+2 =3

so Pressure for A = 0.05 x CRT = 3 x 0.05 x 10 P
= 1.5 P

So a) is the right option

Q2 : - KNO3 is a strong electrolyte so and CH3COOH is a weak one

So i in case of KNO3 is > that in case of CH3COOH

since a=1 for KNO3 and a<1 for CH3COOH and for both n =2

P = iCRT
So at same concentration and temperature

P1 > P2

so d) is the right option !

Jaspreet @ DTU
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#473
Re:SOLUTIONS 2 Years, 5 Months ago Karma: 0

thank you..ur answers r correct but check out da last sentence of Q.no 1.pressure for A..dres a mistake. 



Nandita
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Last Edit: 2010/11/27 15:04 By Nandita.Reason: mistake
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#476
Re:SOLUTIONS 2 Years, 5 Months ago Karma: 0
Oh ya it should be 0.05 x 3 instead 0f 0.05 x C

Anyway just a typing error !

Its ohk if u understood it ! :)

Jaspreet @ DTU
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#477
Re:SOLUTIONS 2 Years, 5 Months ago Karma: 0

kool..u gt it.



Nandita
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